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28u^2+u-2=0
a = 28; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·28·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*28}=\frac{-16}{56} =-2/7 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*28}=\frac{14}{56} =1/4 $
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